Explain the liquefaction of gases with the help of an isothermal graph.

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(N/A) The first complete data on the pressure-volume-temperature relations of a substance in both gaseous and liquid states was obtained by Thomas Andrews for $CO_2$.
From the analysis of the Andrews isotherms:
$(i)$ At high temperatures,isotherms resemble those of an ideal gas,and the gas cannot be liquefied even at very high pressures.
$(ii)$ As the temperature is lowered,the shape of the curve changes,and the data shows a significant deviation from ideal behavior.
$(iii)$ Explanation of $T_C$ (Critical Temperature),$P_C$ (Critical Pressure),and $V_C$ (Critical Volume): At $30.98^{\circ}C$,$CO_2$ remains a gas up to $73 \ atm$ pressure (Point $E$ in the figure). At $73 \ atm$ pressure,liquid $CO_2$ appears for the first time. This point $E$ represents the critical state where the distinction between liquid and gas disappears.

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Similar Questions

Critical constants for a real gas are given as:
$T_C = 180 \ K$; $V_C = 0.123 \ L \ mol^{-1}$
$P_C = 45 \ atm$; $R = 0.082 \ L \ atm \ mol^{-1} \ K^{-1}$
Which of the following statements is correct for this real gas?

At which of the following conditions can a gas be liquefied? ($T_c$ and $P_c$ are critical temperature and pressure.)

Which of the following conditions is most favorable for the liquefaction of a gas?

What is critical temperature $(T_{C})$?

What will be the phase of $CO_2$ at critical pressure $P_C$ and temperatures of $13.1^{\circ}C$,$31.5^{\circ}C$,$50^{\circ}C$,and $30.98^{\circ}C$?

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